mysql查询数据
发布日期:2016-4-27 13:4:5
本文介绍了mysql查询今天、昨天、7天、近30天、本月、上一月数据的方法,参考代码已给出: 1.今天 select * from 表名 where to_days(时间字段名) = to_days(now()); 2.昨天 SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1 3.7天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名) 4.近30天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名) 5.本月 SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' ) 6.上一月 SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1 #查询本季度数据 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now()); #查询上季度数据 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER)); #查询本年数据 select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW()); #查询上年数据 select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year)); 8.查询当前这周的数据 参考代码如下所示: SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now()); 8.查询上周的数据 参考代码如下所示: SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1; 10.查询当前月份的数据 参考代码如下所示: select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m') 11.查询距离当前现在6个月的数据 参考代码如下所示: select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now(); 12.查询上个月的数据 参考代码如下所示: select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m') select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now()) select * from user where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now()) select * from [ user ] where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now()) and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now()) select * from [ user ] where pudate between 上月最后一天 and 下月第一天 where date(regdate) = curdate(); select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now()) SELECT date( c_instime ) ,curdate( ) FROM `t_score` WHERE 1 LIMIT 0 , 30 上一条: Redis 的横向扩展案例 下一条: Redis 未授权访问缺陷
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